Lotto 6/49 Fixed Numbers: How to Calculate Odds of Winning (Even When One Fixed Number Misses)

Using fixed numbers is a practical way to focus budget and improve efficiency. In this guide, we lock 2 fixed numbers in Canada’s Lotto 6/49 so the remaining pool becomes 47, and we show how to calculate lottery odds — rank by rank — under this setting. You will see the probability of winning the lottery in each case and verify everything with the LottoApex Odds Calculator.

This guide explains how to calculate lottery odds in Lotto 6/49 when you use 2 fixed numbers. We keep the official bonus rule (the Classic Draw structure with a bonus ball), we walk through the rank-by-rank math with C(n,r), and we give you a one-click way to verify your probability of winning the lottery in the free LottoApex Odds Calculator.

Contents

  1. What are fixed numbers?
  2. Rank odds with fixed numbers (formulas)
  3. Step-by-step calculations for each rank
  4. When fixed numbers are/aren’t in the winning draw
  5. Check lottery probability instantly in the LottoApex Odds Calculator

1. What are “fixed numbers”?

“Fixed numbers” are numbers you must include in every ticket you generate. In Lotto 6/49, if you lock 2 numbers and choose the remaining 4 freely, your effective candidate pool becomes 47. The total number of unique tickets is then C(2,2) × C(47,4) = 178,365, compared to C(49,6) = 13,983,816 without fixed numbers.

By narrowing the pool, you reduce wasted lines and can evaluate the lottery ticket probability of hitting each rank with far clearer math.

Note: This article covers the Classic Draw with the bonus rule. It does not discuss the separate Gold Ball game.

2. Rank odds with fixed numbers (formulas)

Start with the best-case scenario: both fixed numbers are part of the winning draw. In that case, your working pool is 49 − 2 = 47, so the denominator for odds is C(47, 4) = 178,365 (because each of your tickets already contains the 2 fixed numbers).

Rank Condition (2 fixed) Odds of winning
1st match all 6 (2C2 × 4C4 × 43C0) 1 / 178,365 (≈ 0.0005606%)
2nd match 5 + bonus (2C2 × 4C3 × 1C1 × 42C0) 1 / 44,591 (≈ 0.00224%)
3rd match 5 (no bonus) (2C2 × 4C3 × 1C0 × 42C1) 1 / 1,061.7 (≈ 0.094%)
4th match 4 (2C2 × 4C2 × 43C2) 1 / 32.92 (≈ 3.04%)
5th match 3 (2C2 × 4C1 × 43C3) 1 / 3.61 (≈ 27.68%)

Fundamental identities

Before calculating ranks, memorise these four identities:

3. Step-by-step calculations for each rank

We continue under the assumption that both fixed numbers are in the winning set. The denominator is C(47, 4) = 178,365, because each of your tickets already contains the 2 fixed numbers. Below are the worked examples:

✅ 1st prize — 2C2 × 4C4 × 43C0

Favourable cases = 1
odds of winning the lottery for 1st prize = 1 / 178,365.

✅ 2nd prize — 2C2 × 4C3 × 1C1 × 42C0

Favourable cases = 4
odds of winning the lottery for 2nd prize ≈ 1 / 44,591.

✅ 3rd prize — 2C2 × 4C3 × 1C0 × 42C1

Favourable cases = 4 × 42 = 168
probability of winning the lottery for 3rd prize ≈ 1 / 1,061.7.

✅ 4th prize — 2C2 × 4C2 × 43C2

Favourable cases = 6 × 903 = 5,418
probability of winning a lottery for 4th prize ≈ 1 / 32.92.

✅ 5th prize — 2C2 × 4C1 × 43C3

Favourable cases = 4 × 12,341 = 49,364
lottery probability for 5th prize ≈ 1 / 3.61 (~27.68%).

Rank Formula (2 fixed) Favourable cases Odds
1st2C2 × 4C4 × 43C011 / 178,365
2nd2C2 × 4C3 × 1C1 × 42C041 / 44,591
3rd2C2 × 4C3 × 1C0 × 42C11681 / 1,061.7
4th2C2 × 4C2 × 43C25,4181 / 32.92
5th2C2 × 4C1 × 43C349,3641 / 3.61

4. When fixed numbers are/aren’t in the winning draw

With 2 fixed numbers in Lotto 6/49, the probability of winning the lottery depends heavily on whether your fixeds actually appear in the winning set. Below is a 5th-prize example for three cases (both, one, none). The same structure applies to other ranks — only the formulas change.

How many fixed numbers are in the winning set? Fraction (favourable ÷ total) Favourable cases Total cases Odds Probability
both fixeds (2C2 × 4C1 × 43C3) ÷ (2C2 × 47C4) 49,364 178,365 ≈ 1 / 3.61 ≈ 27.68%
exactly one fixed (2C1 × 4C2 × 43C3) ÷ (2C1 × 47C5) 148,092 3,067,878 ≈ 1 / 20.72 ≈ 4.82%
no fixeds (2C0 × 4C3 × 43C3) ÷ (2C0 × 47C6) 49,364 10,737,573 ≈ 1 / 217.52 ≈ 0.460%

✅ Worked example (5th prize with exactly one fixed)

Favourable cases = 2C1 × 4C2 × 43C3 = 148,092
Total winning-set scenarios (when exactly 1 fixed is in the draw) = 2C1 × 47C5 = 3,067,878
Probability to win the lottery (5th prize in this scenario) = 148,092 / 3,067,878 ≈ 1 / 20.72 (≈ 4.82%)

5. Check lottery probability instantly in the LottoApex Odds Calculator

Feelings can be misleading; numbers aren’t. In the LottoApex Odds Calculator, you can see exactly how your chances of winning the lottery change as you add 0 → 1 → 2 fixed numbers. You can also separate scenarios where the fixeds appear in the winning draw from those where they don’t.

LottoApex Odds Calculator screenshot showing Lotto 6/49 probability with 2 fixed numbers under the Canadian bonus rule
Validate your odds of winning the lottery with fixed numbers using the LottoApex simulator and odds calculator for Lotto 6/49.

Main features:

From fixed numbers to data-validated play

Locking fixed numbers focuses budget—but the real edge appears when you generate and test. The Lotto 6/49 Number Generator leverages a Wheeling System to respect your fixeds, balance coverage, and optimise probability across the remaining pool. Combine fixed + excluded numbers to tune efficiency further.

In the Lotto 6/49 Simulator, play out realistic cases—both fixeds hit, only one hits, or neither hits—and visualise rank distributions. Confirm how your odds shift under each scenario, adjust the build, and repeat until it behaves as intended.

Working cycle: Fix → Generate → Simulate → Verify odds. That’s the bridge from casual picks to strategy.

👉 Try it now: Lotto 6/49 Number Generator
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